geometric challenge

[Bob Jefferson]

[Bazza]

> I'm trying to draw a single panel of an eight-panelled beach ball that is six
> units in diameter. My maths is a bit ropey but would I be right in saying
> that, taking pi to be 3.14, it would be 9.42 long and 2.355 at its widest
> point?

> Does anyone have the means of drawing such a shape and if so could
> they post it here please. There is a point to all this - honest!


My maths is good, but I'm not sure I understand the problem...

You have 8 panels, yeah? And you want to draw a beach ball on these 8 panels? Are the panels arranged 2x4? Or 1x8? What's a "unit"?

[rmolehusband]

[SoupDragon]

Been trying to imagine this.
You have a beach ball made up of 8 panels
The diameter of this beach ball is 6
You want to know the size of a panel you wish to draw from this info?

Would your beach ball panel not need to be oval or rather, elliptical?
( ah , you did say at widest )


The one in my head is now mangled and rather concave after being jumped on in frustration

right so circumference is pi x diameter so thats 3.14 x 6 = 18.84
divide by number of panels is 18.84/8 = 2.355

and length is 18.84/2 = 9.42

but I'm baffled as to how to calculate where to put the pins to follow
of drawing the ellipse

[seanie]

Think of lines of longitude; they converge to a point at each pole. You don't want an ellipse or an oval.

[SoupDragon]

Ah
like chocolate orange segments

[Bob Jefferson]

Thanks to all, and in particular to molehusband. You can get back to work now.

So four of my beach ball panels, with artwork applied, would look a bit like this:



Two would look like this:



And the remaining two would look like this:




Great! Now I can print them off, cut them out and make a scale model.